In one of the discussion forum I saw that last sitting there was a question asking Pr(z>638) for insurance that pays 1000 for one decrement and amount 500 for another decrement. I would really...

1.
payment Y=0 x<=4
X-4 4<=X<=9
5 X>=9

E(Y)= inger{4 to 9}{(x-4) 1/8 exp^-x/8 + 5 exp^-9/8

3.

payment Y = 0 1 2

i found this in another forum. did any body get problem like this in exams.

a guy is trying to sell 3 types of insurance products to 12 people

6 are interested in product A only
4 are...

does anybody know how to solve this problem.

V(u)=72500 lambda
E(u)= 450 lambda
coeff of variation =.90={269.25 (lambda)^.5}/450 lambda}
lambda=2.26 i think

P(at least one loss for high)=.40
P(at least one loss for low)=.10

P(at most 1 person has at least one loss)
=P(o people has at least one loss)+P(1 person has at least one loss)...

reasoning for my previous answer was that:
since i will not be reimbursed for expenses x>2 and y>1 probability of no reimbursement will be P(x>2) and P(y>1).
if it was x=0 and y=0 then answer...

In question no 2 does the question tell u that it was poisson distribution. if not then it sounds like it would be geometric distribution to me. And also i though only geometric and exponential had...

i think it is [sum(x_i * p(x_i) from i = 2 to infinity)]^2 -sum(x_i^2 * p(x_i) from i = 2 to infinity) for variance sicne V[x]=E[x^2]-{E[x}]^2

I dont see why not

I am not sure about this but i think it should be as follows.
X~no of filling
Y~no of root
P(no reimbursement for filling and roots)=P(x>2 and Y>1)
by independence
=P(X>2).P(Y>1)...

[QUOTE=_jared_;28286]I .

Oh and I had one problem that required doing an infinite sum, and it was the kind where you had to integrate it to make it look like a geometric series and then...

do we do 3c2 4c3 3c1/10c6 in this problem

if you guys have free time and if it is possible can you guys please elaborate more (without reconstructing original questions)on what kinds of questions were there in exam. i think it would be...

how come nobody is discussion feb 2008 exam in this website. i thought exams were over

what kind of questions did u guys get this time

can somebody help me with actex problem set 9 -39 P(Y1<1/2<yn)

how come it is not
p[((total value in 100 months -10)/10 >(91-10)/10]=pr(z> 8.1)

i guess it depends on which book you are using

lambda will be number of accidents per month (it is also denoted by mu (depends on book) in poisson distribution)
then lambda =mu=1/theta( here mu...

here is another question from same book
a city engineer has studied the frequency of accidents at two busy intersections. he has determined that the time t in months between accidents at each...

that definetely helped thanks alot nokio.

thanks guys the reason i did not get the right answer was because i forgot to add the part when player actually looses.

nokio if you have time can you please explain why we are not just using...

here is another question from prob for risk management matthew j hassett and donald g stewart
5-5) in the game of ''''s(dice table) the simplest bet is the pass line. the probability of winning such...

answer in back of my book is .2442

are you suggesting p(work in plant A and a minor injury|injury)

i have added the question above