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audia4
August 12th 2005, 09:44 AM
Hello.
I have the following question that I don't have a clue of how to solve:

Let X~exp(0.5) and define Y = min(X,2). Evaluate F_y(3)

Ans: a. e^-1 b. 1-e^-1 c. 1-e^-1.5 d. 0 e. 1

Thank you.

managuense
August 12th 2005, 12:45 PM
Y is the minimum of x and 2 implies the maximum value of Y is 2.
Therefore F_y(3)=prob(Y<=3)=1.