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willborg35
September 13th 2007, 09:26 PM
Under UDD it is assumed exactly that:

Complete expectation of Life = Kurate Expectation of Life + 1/2

Does this apply to the limited expectation of life (related complte(ex:n) =ex:n + 1/2)?

Does anyone know a formula for the limited life expectancy formulas under UDD? Thank you.

MathForMarines
September 30th 2007, 08:43 PM
I don't recall ever having seen one, but I have also done every life con question I could get my hands on, and I never was in a situation in which I would need a formula like that.

Under UDD it is assumed exactly that:

Complete expectation of Life = Kurate Expectation of Life + 1/2

Does this apply to the limited expectation of life (related complte(ex:n) =ex:n + 1/2)?

Does anyone know a formula for the limited life expectancy formulas under UDD? Thank you.

ctperng
September 30th 2007, 09:50 PM
Under UDD it is assumed exactly that:

Complete expectation of Life = Kurate Expectation of Life + 1/2

Does this apply to the limited expectation of life (related complte(ex:n) =ex:n + 1/2)?
Does anyone know a formula for the limited life expectancy formulas under UDD? Thank you.

ctperng

NoMoreExams
October 28th 2007, 02:23 PM
Under UDD it is assumed exactly that:

Complete expectation of Life = Kurate Expectation of Life + 1/2

Does this apply to the limited expectation of life (related complte(ex:n) =ex:n + 1/2)?

Does anyone know a formula for the limited life expectancy formulas under UDD? Thank you.

This is easy to figure out

Complete: e_{x:n} = integral(t_p_x dt from 0 to n) = integral(1 - t/(w-x) dt from 0 to n) = n - n^2/(2(w-x)) = n[1 - n/[2(w-x)]]

Curtate (not Kurate): e_{x:n} = sum(t_p_x from t=1 to n - 1) = sum(1 - k/(w-x) from 1 to n-1) = (n-1) - n(n-1)/[2(w-x)] = (n-1)[1 - n/[2(w-x)]] = n[1 - n/[2(w-x)]] - [1 - n/[2(w-x)]]

So as you can see Curtate = Complete - [1 - n/[2(w-x)]]

Obviously if the sum goes to "infinity" i.e. in this case to w - x, we let n = w-x and we get:

Curtate = Complete- [1 - (w-x)/[2(w-x)]] = Complete - [1 - 1/2] = Complete - 1/2

Hopefully my algebra is right.
________
jugallette (http://juggalos.org)

zmkramer
April 22nd 2008, 03:37 PM
This is easy to figure out

Complete: e_{x:n} = integral(t_p_x dt from 0 to n) = integral(1 - t/(w-x) dt from 0 to n) = n - n^2/(2(w-x)) = n[1 - n/[2(w-x)]]

Curtate (not Kurate): e_{x:n} = sum(t_p_x from t=1 to n - 1) = sum(1 - k/(w-x) from 1 to n-1) = (n-1) - n(n-1)/[2(w-x)] = (n-1)[1 - n/[2(w-x)]] = n[1 - n/[2(w-x)]] - [1 - n/[2(w-x)]]

So as you can see Curtate = Complete - [1 - n/[2(w-x)]]

Obviously if the sum goes to "infinity" i.e. in this case to w - x, we let n = w-x and we get:

Curtate = Complete- [1 - (w-x)/[2(w-x)]] = Complete - [1 - 1/2] = Complete - 1/2

Hopefully my algebra is right.

I got something else, when you do the n-year curtate temporary life expectancy you get

summation of (tPx)

which is 1 - k/(w-x) from 1 to n (NOT n-1)

solving the summation would give you

n - (summation of k from 1 to n)/(w-x) this would give you

n - n(n+1)/2(w-x) which is n - n^2/2(w-x) - n/2(w-x)

so that is continuous e_x:n = curtate e_x:n + n/2(w-x) which would only be 1/2 when n = w-x

which is what ctperng was saying

NoMoreExams
April 22nd 2008, 04:20 PM
I got something else, when you do the n-year curtate temporary life expectancy you get

summation of (tPx)

which is 1 - k/(w-x) from 1 to n (NOT n-1)

solving the summation would give you

n - (summation of k from 1 to n)/(w-x) this would give you

n - n(n+1)/2(w-x) which is n - n^2/2(w-x) - n/2(w-x)

so that is continuous e_x:n = curtate e_x:n + n/2(w-x) which would only be 1/2 when n = w-x

which is what ctperng was saying

booyah

I agree, my summation should go to n not n - 1, however our results agree, when you plug in n = w - x, you get cont = curtate + 1/2, I wrote down curtate = cont - 1/2.

R_T
December 27th 2009, 09:41 PM
Under UDD it is assumed exactly that:

Complete expectation of Life = Kurate Expectation of Life + 1/2

Does this apply to the limited expectation of life (related complte(ex:n) =ex:n + 1/2)?

Does anyone know a formula for the limited life expectancy formulas under UDD? Thank you.

Actually, it's ex:n + .5(1-nPx).