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# Thread: Probability problem (expected value)

1. ## Probability problem (expected value)

Hi just wondering could someone help with this expected value problem??

A middle aged man has an arrangement with his cardiologist whereby in a given month he pays his doctor a visit (at most one) if he has severe heart pains. It is assumed that the chances of
him having such a pain in a given month is .2, and that such pains do not affect in any way pains
occurring later. Let X denote the number of visits to his doctor in a typical year. What are the
mean and variance of X? In any given year the firrst visit costs \$75 while any subsequent visit costs\$50. If C represents the total doctor bill in a given year, what are the mean and variance of C?

2. This problem isn't that complicated, you have to show at least some work

3. Originally Posted by NoMoreExams
This problem isn't that complicated, you have to show at least some work
i know yeah it should be easy but for some reason for expected value of the number of visits to the doctor i was getting 0 as the answer

4. Saying what answer you got isn't showing the work for that answer, provide that and see if anyone can offer any advice as to where you made a mistake (if any).

5. Originally Posted by NoMoreExams
Saying what answer you got isn't showing the work for that answer, provide that and see if anyone can offer any advice as to where you made a mistake (if any).
hmm fair enough here you go i said the expected value for X is (1)(0.2)+(2)(0.2)^2+...12(0.2)^12 which equals to 0.314 so i'm guessing i made a mistake somewhere

6. Originally Posted by Ronan1990
hmm fair enough here you go i said the expected value for X is (1)(0.2)+(2)(0.2)^2+...12(0.2)^12 which equals to 0.314 so i'm guessing i made a mistake somewhere
So are you good now? I'm confused if you are saying the answer should be 0 or .314 or if you got the right answer now.

7. Originally Posted by NoMoreExams
So are you good now? I'm confused if you are saying the answer should be 0 or .314 or if you got the right answer now.
i was wondering was that the right way to do the question i don't know if it's right which is why i posted

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