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Thread: Question on a Practice Exam question

  1. #1
    Actuary.com - Newbie Poster
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    Question on a Practice Exam question

    Hi all,

    I have a question about question #5 from the May 2000 SoA Exam,

    http://www.soa.org/STATIC/examinations.html

    Course 1 under May 2000

    In the solutions it says that it's given that f(t1, t2) = 2/L^2

    I don't understand where that came from...

    Can someone help me out?

    Thanks in advance,

  2. #2
    Actuary.com - Level III Poster
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    Since the distribution is uniform, we can calculate f(t1,t2) as 1/area of region. the shaded region is 1/2 of the L x L square. hence the area of the region equals .5*L^2.

    We need to find 1/area so this is where the 2/L^2 comes from
    [1/(.5L^2) = 2/L^2]

    Just remember that the joint density of a uniform distribution can be calculated as 1/area of region.

    hope that answers your question.

  3. #3
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    I understand now,

    Thanks,

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